tpl: Send actual values to in from intersect

The `intersect` function uses `in` to avoid adding duplicates to the
resulting set.  We were passing `reflect.Value` items when we should
have been using `Value.Interface()` to send the actual data structure.
This fixes that.

See #1952
This commit is contained in:
Cameron Moore 2016-03-13 16:39:03 -05:00 committed by Bjørn Erik Pedersen
parent 600558273e
commit df44b1930a
2 changed files with 4 additions and 4 deletions

View file

@ -330,20 +330,20 @@ func intersect(l1, l2 interface{}) (interface{}, error) {
l2vv := l2v.Index(j)
switch l1vv.Kind() {
case reflect.String:
if l1vv.Type() == l2vv.Type() && l1vv.String() == l2vv.String() && !in(r, l2vv) {
if l1vv.Type() == l2vv.Type() && l1vv.String() == l2vv.String() && !in(r.Interface(), l2vv.Interface()) {
r = reflect.Append(r, l2vv)
}
case reflect.Int, reflect.Int8, reflect.Int16, reflect.Int32, reflect.Int64:
switch l2vv.Kind() {
case reflect.Int, reflect.Int8, reflect.Int16, reflect.Int32, reflect.Int64:
if l1vv.Int() == l2vv.Int() && !in(r, l2vv) {
if l1vv.Int() == l2vv.Int() && !in(r.Interface(), l2vv.Interface()) {
r = reflect.Append(r, l2vv)
}
}
case reflect.Float32, reflect.Float64:
switch l2vv.Kind() {
case reflect.Float32, reflect.Float64:
if l1vv.Float() == l2vv.Float() && !in(r, l2vv) {
if l1vv.Float() == l2vv.Float() && !in(r.Interface(), l2vv.Interface()) {
r = reflect.Append(r, l2vv)
}
}

View file

@ -776,7 +776,7 @@ func TestIntersect(t *testing.T) {
sequence2 interface{}
expect interface{}
}{
{[]string{"a", "b", "c"}, []string{"a", "b"}, []string{"a", "b"}},
{[]string{"a", "b", "c", "c"}, []string{"a", "b", "b"}, []string{"a", "b"}},
{[]string{"a", "b"}, []string{"a", "b", "c"}, []string{"a", "b"}},
{[]string{"a", "b", "c"}, []string{"d", "e"}, []string{}},
{[]string{}, []string{}, []string{}},